If the difference between the circumference and diameter of a circle is 60 cm. then the radius of the circle is

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ATQ,
$$\begin{gathered} 2\mathrm{\pi r} -2\mathrm{r}= 60 \\ \Rightarrow 2\mathrm{r} (\mathrm{\pi }-1) =60 \\ \Rightarrow \mathrm{r}=\frac{30}{\mathrm{\pi }-1}=\frac{30}{{\displaystyle \frac{22}{7}}-1} \\ =\frac{30}{{\displaystyle \frac{22-7}{7}}}=\frac{30}{{\displaystyle \frac{15}{7}}} \\ =\frac{30}{15}\times 7 \\ =14 \end{gathered}$$